Answer:
Decay constant : -0.050817
No = 355.3
We know that decay constant, λ=ln(Nt/No)/t
Nt= Amount of the sample at time t
= ln(11.9/No)/13 = ln(6.54/No)/37
= (11.9/No)/13 = (6.54/No)/37
= (11.9/No) x 37 = (6.54/No) x 13
= ((11.9/No) x37) - ((6.54/No)x13)
No = 440.3 - 85
No = 355.3
To find decay constant ,
λ= ln(0.84/355.3)/119
= -0.050817
Please help! This is my last one and I never really done a decay problem like...