L uestion from this section) Question 5 A simply supported beam has a span of 6...
A simply supported wood beam of rectangular cross section and span length 2 m carries a uniformly distributed load of intensity 9 = 1 kN/m as shown. Calculate the maximum bending stress and the maximum shear stress in the beam.
5. Determine the mid-span short-term deflection of a simply supported beam with the section shown in Figure Q5. Design data: Concrete strength: fcu 30 MPa. Area of tensile steel reinforcement: As 1500 mm Area of compressive steel reinforcement: A,-1500 mm2 Instantaneous static modulus of elasticity of concrete = 25GPa. Span -8.0 m Loading: Dead load 5.0 kN/m (uniformly distributed load); Live load 5.0 kN/m (uniformly distributed load) (Hint: the height of neutral axis of the mid-span section under the service...
A simply supported wood beam AB with span length L = 6 m carries a trapezoidal distributed load of intensity q = 4 kN/m at the left end and q/2 at the right end. Calculate the maximum bending stress Omax due to the load if the beam has a rectangular cross section with width b = 150 mm and height h = 250 mm.
The beam ABC is supported at A with a guided support (fixed with roller) and hinge at B has rectangular cross section and supports concentrated loads P both ends A and C as shown in the figure. The span length from A to Bis L, and the length of the overhang is 1/2. Point D is located midway between the supports at a distance d from the top face of the beam Knowing that the maximum tensile stress (principal stress)...
The beam ABC is supported at A with a guided support (fixed with roller) and hinge at B has rectangular cross section and supports concentrated loads P both ends A and C as shown in the figure. The span length from A to B is L, and the length of the overhang is 1/2. Point D is located midway between the supports at a distance d from the top face of the beam Knowing that the maximum tensile stress (principal...
Q6 (12 marks) In the figure below, the steel beam ABC is simply supported at A and C. Its cross-section is the rectangular tube as shown where dimensions are in in. Force F varies such that the magnitude of deflection at the mid-span of the beam is between 0.01" and 0.05". Determine the mean stress and alternating stress developed at the top surface of cross-section B. Given, a = 7", b = 12". A ab — In Simple supports 4X2X1/4...
A prismatic beam with span L = 3 ft is simply supported at points A and B. The beam is supporting a uniform load with q = 160 lb/in . The cross-section of the beam is a solid rectangle with width b = 1 in and height h = 4 in . Determine: a. The normal stress (σ C ) and shear stress (τ C ) at point C located 8 inches left of support B and 1 in. below...
Figure 2 shows a simply supported beam and the cross section at mid span. The beam supports a uniform service (unfactored) dead load consisting of its own weight plus 1.4 kips/ft and a uniform service (unfactored) live load of 1.5 kips/ft. The concrete strength is 3500 psi, and the yield strength of the reinforcement is 60,000 psi. The concrete is normal-weight concrete. For the midspan section shown in Figure 2, compute фМп and show that it exceeds Mu. WD 1.4...
14.54 A simply supported rectangular beam with a span of 6 ft has a concentrated load of 4.1 kip at midspan. Se- lect the lightest rectangular wood beam that can safely support the loads (neglect the weight of the beam). The allowable stress in bending is 1200 psi and in shear parallel to the grain 100 psi 14.54 A simply supported rectangular beam with a span of 6 ft has a concentrated load of 4.1 kip at midspan. Se- lect...
a simply supported beam shown has a span length of 16 ft. the beam is laoded with to concentrated service live loads of 40 kips and 80 kips as shown. if lateral support is provided only at both ends, select the lightest w section of A992 steel that can carry these applied loads. neglect the weight of the beam. ***Need this answered ASAP please*** ***Please show ALL steps*** steel design - please show what tables the values come from. thank...