Calculate the pH at the following points in a titration of 40 ml (0.040 L) of 0.100 M barbituric acid (Kà= 9.8x10^-5) with 0.100 M KOH
a. no KOH added
b. 20 ml of KOH solution added
c. 39 ml of KOH solution added
d. 40 ml of KOH solution added
e. 41 ml of KOH solution added
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Calculate the pH at the following points in a titration of 40 mL (0.040 L) of 0.133 M barbituric acid (K (a) no KOH added 1 244 - 9.8x105) with 0.133 M KOH. (Assume K - 1.01x10-44) (b) 20. mL of KOH solution added 04.01 (c) 39 mL of KOH solution added 5.6 (d) 40. mL of KOH solution added (e) 41 mL of KOH solution added 11.09
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Consider the titration of 40.0 mL of 0.200 M HCIO4 by 0.100 M KOH. Calculate the pH of the resulting solution after the following volumes of KOH have been added. a. 0.0 mL pH = b. 10.0 mL pH = c. 60.0 mL pH = d. 80.0 mL pH = e. 110.0 mL pH = Consider the titration of 100.0 mL of 0.200 M acetic acid (Ka = 1.8 x 10-5) by 0.100 M KOH. Calculate the pH of the...
23) What is the pH of a solution prepared by mixing: 0.20 moles of acetic acid 0.40 moles of sodium acetate 0.10 moles of sodium hydroxide in 1.0 L of solution a) 4.74 b) 4.14 5.34 d) 13.00 e) None of the above 24) Barbituric acid (Ka = 9.8 X 10-5) is titrated with 0.200 M NaOH. What is the initial pH of 20.0 mL of 0.100 barbituric acida) 2.50 b) 4.01 c) 8.35 d) 7.00 e) None of the above 25) What is the pH in...
Rolerences Consider the titration of 100.0 mL of 0.200 M acetic acid K = 1.8 x 10-5) by 0.100 M KOH. Calculate the pH of the resulting solution after the following volumes of KOH have been added. a. 0.0 mL pH = b. 50.0 mL pH = c. 100.0 mL pH = d. 130.0 mL pH = e. 200.0 mL pH = f. 210.0 mL pH = Submit Answer TEY Another Version 6 ltem attempts remaining.
(ueak acid/shing base 3. Calculate the pH at the following points for the titration of 25.0 mL of 0.100 M formic acid (Ka-1.80 x 10") with 0.100 M NaOH: VNOH 0.00 mL, 15.00 mL, 25.00 mL, 40.00 mL. Draw a graph of pH vs. VaoH. (30 points) (b) Buffer capacity can be thought of as how well a solution resists changes in pH after a strong base/acid is added. A buffer is most effective to resisting pH changes when what...
Consider the titration of 100.0 mL of 0.200 M acetic acid ( Ka = 1.8 x 10-5) by 0.100 M KOH. Calculate the pH of the resulting solution after the following volumes of KOH have been added. a 0.0 mL pH= 50.0 mL pH = C 100.0 mL pH = 140.0 mL pH= C 200.0 mL pH = f 240.0 mL pH=
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Consider the titration of 100.0 mL of a 0.0570 M solution of the hypothetical weak acid H3X (Ka1 = 4.4x10-3 , Ka2 = 4.4x10^-7, Ka3 = 4.4x10^-12) with 0.100 M KOH . Calculate the pH of the solution under the following condition: 1) after 228.0 mL of 0.100 M has been added pH =