40) a) Number of 5 card hands possible with exactly 3 aces
= number of ways of selectng 3 aces from 4 cards x number of ways of selectng 2 cards from 48 non aces
= 4C3 x 48C2
= 4512
b) Number of ways to select 3 aces and 2 kings = 4C3 x 4C2
= 24
c) Number of ways to select three of one kind and two of another = 24 x number of ways in which 2 kinds can be chosen from 13 available
= 24 x 13C2
= 1872
Can someone answer this question with solution? From an ordinary deck of 52 cards, how many...
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