A harmonic wave moving in the positive x direction has an amplitude of 3.7 cm, a speed of 42.0 cm/s, and a wavelength of 42.0 cm. Assume that the displacement is zero at x = 0 and t = 0.
Calculate the displacement due to the wave at x = 10.0 cm, t = 20.0 s.
Equation for a Harmonic Wave is y = A Sin(kx-Wt+P), P is phase
Given A=3.7 cm
k=2*pi/42
v = 42cm/s = W/k , so, W = k*v = 2*pi
Given displacement is zero at x = 0 and t = 0 so, P =0
So,
y = A Sin(kx-Wt)
At x = 10.0 cm, t = 20.0 s,
y = 3.7 sin((2*pi/42)*10- 2*pi*20)
y = 3.7 sin((20pi/42)-40pi)
y = - 3.06 cm
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