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Under an applied axial load of 3,806 kN, the diameter of a bar decreases by 0.23 mm from an original diameter of 149 mm. Pois

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a axial load (P) = 3806 KN Change in diameter (Ad)= -0.23 mm -ve sign represent, value of diameter is decreased original diamlongitudinal stain (E) = 1.54410-3 = 4.16 *10-3 0.37 Cross section Area (A) = Æxd² = 17 x (149² = 17436.62 mm² = 0.0174 m² stX E = EXE (E=elastic modulus) . = 218.27 = 52.470 x 103 MPa 4. 16410-3 = 52.470 Gpa

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