Homework Answers
a)
Force of tension = mg sin theta
F = 5.55*9.81*sin 62
F (tension ) = 48.07 N
b)
Force of traction = mg sin theta
F = 5.55*9.81*cos 62
F (traction) = 25.56 N
T = 5.55*9.8 =54.39 N
b) horizontal traction force
T cos 62 + T = 79.92 N
vertical tractin force = Tsin62 = 48.025 N
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