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The femur of a human leg (mass 10 kg, length 0.9 m) is in traction, as shown in the figure. The center of gravity of the leg

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Answer #1

T(/3 T2(21/3) Mg(0)+8g(0) T1 = 212 m1 2m2 Now equating forces along y, so that the net forces should be zero m1- 2m2 m2- M/3

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