Question

To create X-rays, a strong electric field is placed between an anode and a cathode. Electrons are then disconnected from the cathode and accelerated toward the anode. When they enter the anode, X-rays are created. In this case, the cathode is placed in x = 0, and the anode in x = 90 cm. The voltage between them is Uka 90 kV. You can assume that the electric field is homogeneous Determine the potential electrical energy of the electron W W1 W2... W10] in the points indicated by the vectorx. The charge of the electron is -1.602e-19 C. Do not ignore rounding this time. The potential energy is also zero at the cathode.

Answer 1

The cathode is placed in x = 0 and anode is placed at x = 90 cm. The voltage between anode and cathode = 90 times 10^3 volt and the electric field between the plates are homogenous Now the potential electrical energy x rightarrow x = x x = 90 at a vector x electric field at x, E = v/d times x 90 times 10^3/90/1w . 90/100 x = 10^5/(90/1w) x Therefore electric field at a point x = 10^7/90 x v/m Now potential energy of electron w = E . e = 10^7/90 x times 1.6 times 10^- 19 w = 1.77 times 10^- 14 x