Question

In Java create an integer array named dice1 with a size of 10. Populate each array location with a roll of a six-sided die (hint: an int value of 1 through 6). Print the array out using an enhanced for loop.

Sample output:

Question 1
dice1 = 1 1 6 2 3 5 1 5 4 5

Answer 1

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SOLUTION:

import java.util.Random;
public class Main
{
   public static void main(String[] args) {
       int dice1[]=new int[10];
       //array to store dice values
       Random rand = new Random(); //random number generation instance
       for(int i=0;i<10;i++){//loop to store data of dice with random number
       dice1[i]=rand.nextInt(6)+1;
       //here i am generating random number from 0 to 5 and then adding 1
       //to get random number from 1 to 6
       }//print the dice values
       System.out.print("dice1 = ");
       for(int i=0;i<10;i++){
       System.out.print(dice1[i]+" ");
       }
   }
}

CODE IMAGE:

ava import java.util.Random; public class Main public static void main(String[] args) { int dice1[]=new int[10]; //array to store dice values Random rand = new Random(); //random number generation instance for(int i=0;i<10;i++){ // Loop to store data of dice with random number dice1[i]=rand.nextInt(6)+1; //here i am generating random number from @to 5 and then adding 1 //to get random number from 1 to 6 }//print the dice values System.out.print("dice1 = "); for(int i=0;i<10;i++){ System.out.print(dice1[i]+" "); input dicel = 3 2 3 1 3 6 5 5 4 5