Question

100. mL of 0.200 MHCl is titrated with 0.250 M NaOH. Part A What is the pH of the solution at the equivalence point? Express the pH numerically. View Available Hintis)

Answer 1

Q Volume of HCl 100 ml = 0.11 CV) Molarity Of HCI 0.2M (MI) molarity of NaOH = 0.25M CM2) Volume of NaOH CV₂) Mivi M2 0.2 x 0.1 0.08 € 0.25 molarity equation : MiVia M₂ Vz

No. of moles of HCI > molarity x volume 2 0.02 0.2 x 0.1 No. of Na O H = 0: 25 x O OB = O O2 moles of As so they they ionize Hal and NaOH are strong acid and bases respectively so completely ie CHCI) [ht] and [NaOh] -[on] Total amount of [ht] left after neutrali zing Cond determines the ph. so, catego no. of moles of [ht J = 0.02 No. of moles of [oh 20:02 so, all (H+) is consumed by Con 72e solution So, PH is is neutral.