Question

Experiment 1 Time (hours) [A] (M) 0 1.00 x 10^(-1) 1 1.10 x 10^(-2) 2 2.20...

Experiment 1
Time (hours) [A] (M)
0 1.00 x 10^(-1)
1 1.10 x 10^(-2)
2 2.20 x 10^(-3)
3 2.80 x 10^(-4)
4 2.00 x 10^(-5)
5 3.50 x 10^(-6)
Experiment 2
Time (hours) [A] (M)
0 1.00 x 10^(-1)
1 6.07 x 10^(-2)
2 3.80 x 10^(-2)
3 2.00 x 10^(-2)
4 1.35 x 10^(-2)
5 7.50 x 10^(-3)

Experiment 1 starts with [A] = 0.1 M and [B] = 6.0 M. Experiment 2 starts with [A] = 0.1 M and [B] = 3.0 M. Use [A] as a concentration of time.

What is the rate law? Support with a graph. Show steps.

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Answer #1

Inc 1/c 10 0.011-4.50986 90.90909 2 0.0022-6.1193 454.5455 3 0.00028-8.18072 3571.429 4 0.00002 10.819850000 5 0.0000035 -12.

best fit for experiment 1 is FIRST ORDER, k = -slop2 = 2.0655 1/h

Q2.

For the second experiment:

1/C InC 1/c 150 100 50 10 0 10.0607 -2.80181 16.47446 2 0.038-3.27017 26.31579 0.12.30259 0.02 -3.91202 4 0.0135 -4.30507 74.similar,

the best fit is FIRST ORDER

with k= -slope = 0.5172

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