Question

4. True or false? (+1 for each correct answer, -1 for each incorrect answer, 0 for each omitted answer) (a) f(N) = N(t(N)) en

@) f(N) = O(t(N)) entails t(N) = 0(f(n)) (f) t(N) = o(f(n)) entails t(N) = 0(f(n))

6. Prove that if I(N) = o(fiN) + g(N)) and g(N) = off (N)) then I(N) = O(fN)). Hint: review how I proved another algebraic bi

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Answer #1

4.a) True

b. ) False

c) True

d) False

e) True

f) True

6) T(N) =O(f(N) +g(N)) which implies T(N)<=c*f(N) +c*g(N) for some positive constant c>0.......(i)

As g(N)=o(f(N)) which implies g(N) < k*f(N) for any positive integer k >0...........(ii)

So T(N) <= c* f(N) + c*k*f(N) [from i and ii ]

Hence T(N)<= r* f(N) where r =c+c*k

Hence T(N)=O(f(N)). [proved]

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