Given that Volume flow rate is given by:
Q = pi*r^2*v
r = radius of aorta = 14 mm = 14*10^-3 m
v = speed of blood flow = 20 cm/sec = 0.20 m/sec
So,
Q = pi*(14*10^-3)^2*0.20
Q = 0.123*10^-3 m^3/sec
Since 1000 L = 1 m^3, and 1 min = 60 sec, So
Q = (0.123*10^-3 m^3/sec)*(1000 L/1 m^3)*(60 sec/1 min)
Q = 0.123*10^-3*1000*60 L/min
Q = 7.38 L/min = 7.4 L/min
Correct option is A.
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