Q #1 Solve for the gain A-Vo2/Va, if V.-1V, Kn_HnCox = 0.4mA/V, VDD = 12V,-Vss--12V, (W/L)t® 12V 40? Vo2 Vd M3 -12V -12V
8. Use Nodal Analysis to solve for V 10V 411 40 12V 60
P 1.43 Part A we know that t 10V,v,"-3V,u,-12V, and th _ 3 V, solve for the voltage ta in figure. (Figure 1) Express your answer to three significant figures and include the appropriate units Iva = | Value Units Figure く, 1011 Submit Request Answer Part B We know that ta . 10v.n.-3V,u/-12V, and th . 3 V . solve for the voltage ve İn figure. Express your answer to three significant figures and include the appropriate units Units...
2) Given an AC voltage source v(t) i(t) 10v2 cos(2T60t +60°) A, determine the relationship ot their phase angles i(t) leads v(t) bydegree (write your solution between -180 and +180 degree). 120V2 cos(2π60t + 30°) V whose current output is 3) Given an AC voltage source v(t) 120v2 cos(2T60t+30°)V whose current output is i(t) = 10V2 cos(2 π60t + 345°) A, determine the relationship of their phase angles: t) lags vit) by degree (write your solution between-180 and 180 degree)
2. In the circuit below, if Vo 24V,determine V. answer: V, 12V 3Ω 5Ω 6Ω 0-
250 60 100 a ww + 12V 402 350 (a) 6 Q 102 82 + >140 3A 202 b (b) . In the above circuit determine the following: (a) Equivalent resistance R (b Currentsi, and i (b) Voltage V
suppose that the voltage (12V) varies linearly from 6 to 18 V as t varies from 0 to 10 min. If i=2A during this time, find (a) the total energy supplied and (b) the total charge delivered to the battery.
7.12 The electric field of an elliptically polarized plane wave is given by [-k 10 sin(cot-kz-60°) E(z, t) y 30 cos(ot - kz)] (V/m). Determine the following: (a) The polarization angles (y, x). (b) The direction of rotation.
7.12 The electric field of an elliptically polarized plane wave is given by [-k 10 sin(cot-kz-60°) E(z, t) y 30 cos(ot - kz)] (V/m). Determine the following: (a) The polarization angles (y, x). (b) The direction of rotation.
r(t) = 10 sin(300t + 60°) cos(x - 90) sin(x) v(t) 10 cos(300t- 30°) ω = 300, Mag = 10, θ =-30° v 102-30 MLP Mcos(P) +jMsin(P) v = 10 cos(-30) +j10 sin(-30) Step 1: Convert to Cosine Step 2: Identify Frequency, Magnitude, and Phase Step 3: Convert to real/imag form = 8.66-J5 Step 4: Solve Step 5: Convert Back
Page T Ri 20 Ω 12V E,-18 V 3.0 V 0.52 S 0.25 Ω E. Rs 15 2 0.75 Ω 24 V Kirchhoff's loop rule applied to loop afedcba. Fill the blanks in terms of left-hand side in terms of the variables R, r. I, E1, and Es Do not use numerical values. 1T1 -E1 11R, = 0