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4. Suppose you have a system of N-10 quantum harmonic oscillators described by the Boltzmann distribution. The total energy in the system is M-40ho a) What is the average oscillator energy? b) What is the probability that an oscillator has twice the average energy?

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I attached my all calculation. I hope u will understand thank you ?

Given, N = 10 Total energy 40*, 4 ото, е) Ava - ская, 8 = ТО CS Scanned with CamScanner — 4*,we know, Energy of harmonic oscillator is given by (+4) nwo v=0, 1, 2 The be , I (v + {) two - 40hw. = 40 5) ² + 3 + 2 = 80 3Therefore the levels are It the cea 15 - 20 ze 9-level 3 hw, a & ½ two = & The probability - Shwß |:{= 2x Avg, energy e = 8ħAlso, Total energy 3 28 NKT - 40hh 15 КТ с 40 ho КТ - hWo Е, к1 3 hю. Hence, p= -24 54. у. [с(e-) е.. 45 — e°Ce ~) e 2 980 -

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