Question

please find p-value

Passed Failed 20 16 Results from a civil servant exam are shown in the table to the right. Is there sufficient evidence to support the claim that the results from the test are discriminatory? Use a 0.01 significance level. White candidates Minority candidates 8 28 Determine the null and alternative hypotheses. O A. Ho: A white candidate is more likely to pass the test than a minority candidate. Hy: A white candidate is not more likely to pass the test than a minority candidate. O B. Ho: White and minority candidates do not have the same chance of passing the test. Hy: White and minority candidates have the same chance of passing the test. O C. Ho: A white candidate is not more likely to pass the test than a minority candidate. Hy: A white candidate is more likely to pass the test than a minority candidate. D. Ho: White and minority candidates have the same chance of passing the test. H: White and minority candidates do not have the same chance of passing the test. Determine the test statistic. (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. ?

Answer 1

	#observed frequency
		passed	failed	Total
	White candidates	20	16	36
	Minoritoy Candidates	8	28	36
	total	28	44	72

#Expected frequency

Ei=Σrow*Σcolumn/Σtotal	passed	failed	Total
White candidates	14	22	36
Minoritoy Candidates	14	22	36
total	28	44	72

chi square    χ2	=(Oi-Ei)2/Ei	passed	failed	Total
	White candidates	2.571428571	1.636363636	4.207792
	Minoritoy Candidates	2.571428571	1.636363636	4.207792
	total	5.142857143	3.272727273	8.415584

$\chi^2=\sum{}(Oi-Ei)2/Ei$=8.41558

#test statistics=8.416

degree of freedom =(r-1)*(c-1)=(2-1)*(2-1)=1

P-value=P($\chi^2$>8.416)=0.0037

value of chi-square obtain from chi-square table with the corresponding degree of freedom

#P-value=0.0037