Homework Answers
Applied tension in the block=120 N
Angle of force with horizontal=45 degrees
Horizontal force=120*cos45=84.85 N
Verttical force =120*sin45=84.85 N
Weight of block=10 *9.8=98 N
Normal force from ground on block=98-84.85=13.15 N
Friction force=0.15*13.15=1.97 N
Net horizontal force on block=84.85-1.97=82.88 N
Mass=10 kg
Acceleration=82.88/10=8.288 m/s²
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