Question

8) The coefficient of kinetic friction between the object and the table is uk= 0.150 Determine the acceleration of the object
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Answer #1

Applied tension in the block=120 N

Angle of force with horizontal=45 degrees

Horizontal force=120*cos45=84.85 N

Verttical force =120*sin45=84.85 N

Weight of block=10 *9.8=98 N

Normal force from ground on block=98-84.85=13.15 N

Friction force=0.15*13.15=1.97 N

Net horizontal force on block=84.85-1.97=82.88 N

Mass=10 kg

Acceleration=82.88/10=8.288 m/s²

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