Part A is wrong and I need help Entered Answer Preview [le^t)/y]+5*cos(5*t)*([-x/(y^2)]+(1/2))+[(6*y/(z^2)]* sin(6*t) 5 +5.2015) (+)+ sino 0.916666666666667 11 12 (1 point) x Suppose w = + where у x = e', y = 2 + sin(5t), and z = 2 + cos(6t). Nie A) Use the chain rule to find was a function of x, y, z, and t. Do not rewrite x, y, and z in terms of t, and do not rewrite e as x. dw dt...
At least one of the answers above is NOT correct. (1 point) Suppose f(x, t) = e 3t sin(x + 2t). (a) At any point (x, t), the differential is df = e^(-3t)cos(x+2t)dx+(e^(-3t))(2cos(x+2t)-2sin(x+2t))dt (b) At the point (-1,0), the differential is df = cos(-1)dx+(2cos(-1))+3sin(-1)dt (c) At the point (-1,0) with dx = -0.5 and dt = 0.3, the differential is df = 0.97344 Note. You can earn partial credit on this nrohlem (1 point) Consider the surface xyz = 20....
Find dz d given: z = xeyy, x = = to, y= – 2 + 2t dz dt Your answer should only involve the variable t. Let z(x, y) = xºy where x = tº & y = +8. Calculate dz by first finding dt dx -& dt dy and using the chain rule. dt dx d = dy dt Now use the chain rule to calculate the following: dz dt
art 1 sin(5t)) z(t) = (cos(50t) + x(t))?, where x(t) = }. z(t) is passed through a filter with impulse response h(t) in order to pass only the product 2x(t) cos(50t). Which filter below is the correct filter to do that? ST sin(5t) sin(15t) / (a) h(t) = {* tt at (b) h(t) sin(5t) sin(100) L 1. Tt at os(1004) 5 it - Tt J (c) h(t) = {i sinft) sin15)} 2cos(50) (a) h(e) = { i sin tuon )*2...
Can someone explain how to do this problem? 2. Let f(t, y) — х +у, 0<x< 1, 0 <y<1 < ,Y < !) (a) Find P (X 1 2 (b) Find P(X < 2Y)
Numbers 1 and 2 please • Giren f(x, y, z) = ye" + x1nz Find E, ly, la, tra, Exy 2 Given w= xy + y +XZ. X= s. cost y=s. sint z =t Find dw and dw dt
12. Find the current in a circuit if the power is 500 W (watts) and the resistance is 25 ohms. Round off your answer to two decimal places p Use the formula I = O A. 0.05 A B.0.22 A C. 4.47 A D. 20 A 13. Solve the expression for x: (4 2) (x - 2) 4x - 8 A.x 0 B.x-2 c. x 6/s D. x 2 14. Solve the following equation for 2 /4y 3 11. А....
2. In the lecture the general solution to the Legendre equation (1-z?)y', _ 2 ry, + n(n + 1)У-0.TIER. х є R series u(x) and ():(r) don(r) + of convergence of y1 (a), y2(z) considering: (i) the paraneter n is nonnegative înteger, n є N; (ii) the parameter n is not an integer, n ¢ Z. [Do not derive these series, refer to the relevant results obtained in lecture] 2. In the lecture the general solution to the Legendre equation...
Consider the following. w = In(x2 + y), x = 2t, y = 5 - t (a) Find af by using the appropriate Chain Rule. (b) Find by converting w to a function of t before differentiating. -/1 POINTS LARCALC11 13.R.054. Differentiate implicitly to find oux x2 = 9 x + y -11 POINTS LARCALC11 13.R.069. Find an equation of the tangent plane to the surface at the given point. z = x2 + y2 + 9, (1, 2, 14)
(1 point) Use the chain rule to find ow, where u0 = xy + yz,x = d, y = e sin t, z = e cost First the pieces: Now all together: dw = dw dx + dw dy + dw dz is too horrible to di – og det du di + Öz do is too horrible to write down (correctly).