Question

Entered Answer Preview [le^t)/y]+5*cos(5*t)*([-x/(y^2)]+(1/2))+[(6*y/(z^2)]* sin(6*t) 5 +5.2015) (+)+ sino 0.916666666666667 11 12 (1 point) x Suppose w = + where у x = e', y = 2 + sin(5t), and z = 2 + cos(6t). Nie A) Use the chain rule to find was a function of x, y, z, and t. Do not rewrite x, y, and z in terms of t, and do not rewrite e as x. dw dt = e^t/y+5cos(5t)(-x/y^2+1/2)+6y/z/2 (sin(6t)) Note: You may want to use exp) for the exponential function. Your answer should be an expression in x, y, z, and t; e.g. "3x - 4y" B) Use part A to evaluate dw when t = 0. dt 11/12

Part A is wrong and I need help

Answer 1

Using chain rule we get the required result.
briven that, wa IN Where 9 xzet - 2+ Sin (5+) and za 2 + cos (67) Non chain rule and get uning dw aw dn aw an de aw dz dt dt df (1) + + he again, and (+4)=4+0-ty ar ġ ) --ýzt 2 / 2 (4 + 2) ow + 1 he y row - z? ZI 2 du at dy at 2 at acet)= et u 2+ sin(St)) = 0 +56055t) = 5 cos (5+) 2+ Cos (6+)) - (6+)) - 0-6 sin(6+) = -6 sin(6+) - dz dt at (

et At tro, xa eº-1, - 27 Sin (50)) = 2+0 -2 From (1) dw at &w dt + 5 + (gr+te) 5705(5+) – Ž=(-4 - 6 Sin6+)) G1 / 2 Sin (or) e Lolo ģ2+2) cos(s+) + 2 = 27Cos(660) = 2+ Cos (0) = 2+1=3 At tzo, , 151, 7-2, 223 [4] tots(****) (569) + Sales, sin(sco) Ź +5 (-++3) Cos (0) + $+505322(y + Ź +5 (42) ) 12 sin(o) 9 (1 + 13.com V = U 12 675 12 dw U. dt 12 .: At