Homework Answers
molecular formulae of the compound is C10H14.
Degree of unsaturation = 10 - (14/2) + 1 = 4
A peak at around 3000 cm -1 indicates the presence of a benzene ring with a degree of unsaturation of 4.
The 1H NMR spectrum conforms the presence of only 2 different types of H - atoms. The peak at arounf 7 ppm represents the benzene hydrogen. Hence the compound should be tert - butylbenzene.
Add Answer to:
Draw the organic structure that is represented by the
following spectra:
R Spectrum 1600 1200 800...
Draw the organic structure that is represented by the following spectra: R Spectrum Mass Spectrum absorption...
Draw the organic structure that is represented by the
following spectra:
R Spectrum Mass Spectrum absorption above 220 m 40 80 120 200 240 200 C NMR Spectrum 200 160 120 80 H NMR Spectum 10 る(ppm) Problem 71 Loc 2122 of 3148 74%
Problem 19 IR Spectrum 2000 1600 1200 800 100 Mass Spectrum No significant UV absorption above...
Problem 19 IR Spectrum 2000 1600 1200 800 100 Mass Spectrum No significant UV absorption above 220 nm 40 M+ 147149 40 80 120 160 200 240 280 m/e 3C NMR Spectrum (100 MHE, CDC, solution) proton decoupled 200 160 120 40 0 8(ppm) H NMR Spectrum 22 ppm 8 5 2 δ(ppm)
Find the structure IR Spectrum quid 4000 3000 2000 V (cm 1600 ) 1200 800 0.0...
Find the structure
IR Spectrum quid 4000 3000 2000 V (cm 1600 ) 1200 800 0.0 Mass Spectrum 0.5t of base peak UV spectrum 1.075 mg/10ms path length: 0.10 cm solvent: ethanol CH100 280 1.5 40 80 120 160 m/e 200 240 200 250 cm 300 13C NMR Spectrum (1250 MHZ COCI, solution) DEPT CH CH CH! proton decoupled 200160120 80 40 08 (ppm) TH NMR Spectrum (600 MHz, CDCI, solution) expansions expansion pom 10 9 8 7 6 5...
Problem 50 IR Spectrum 2000 1600 1200 800 V (cm) Mass Spectrum 80 No significant UV...
Problem 50 IR Spectrum 2000 1600 1200 800 V (cm) Mass Spectrum 80 No significant UV absorption above 220 nm 60 40 80 120 160 200 240 280 m/e 13C NMR Spectrum proton decoupled 200 160 120 40 0 8(ppm) H NMR Spectrum (200 봐な. CDC, solution) 4.0 10 δ (ppm)
Label the spectra and propose a structure for the compound. Compound 2 R Spectrum Bedie 3400...
Label the spectra and propose a structure for the compound.
Compound 2 R Spectrum Bedie 3400 1720 4000 3000 2004 1600 vomi) 1200 800 183 Mass Spectrum Softbase de UV Spectrum . mar 253 nm 109,96 26) mas 250 nm 109,2.7) 2 mar 284 m 109,0 2.5) M -220N) CH2O 280 40 80 120 160 200 240 13C NMR Spectrum (100 . CDC, DEPT CH Chicht protondeco 200 160 120 80 400 (ppm) 'H NVR Spectrum (400MCDO, Exchanges wayo Exchanges...
Attached are four spectra for isomer with the MF= c12h14o4. Determine the structure for each molecule...
Attached are four spectra for isomer with the MF=
c12h14o4. Determine the structure for each molecule and draw them
below.
problem 63 IR Spectrum (CCI, solution) 1765 4000 3000 1200 800 2000 V (cm ) Mass Spectrum UV Spectrum & 8 8 g 8 of base 2 mar 269 nm (10910€ 2.7) humax 263 nm (10910 2.7) M -222 (< 1) 169 sahent: methanol 8 C12H1404 240 280 40 80 120 160 200 13C NMR Spectrum (50.0 MHz, COCI, solution)...
determine the compound structure based on the spectrums. please explain. IR Spectrum liquid rim) 1600 1200...
determine the compound structure based on the
spectrums. please explain.
IR Spectrum liquid rim) 1600 1200 800 4000 3000 2000 V (cm') 100 콩2 No significant LV absorption above 220 nm 40 3 C6H1004 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (S0.0 MH, CDC, solution) proton decoupled 40 0 δ(ppm) 200 160 120 80 H NMR Spectrum (200 MHz, CDCi solution) 10 9 8 76 5 4 3 2 1 0 8 (ppm)
Problem 4 IR Spectrum ud 1600 LL 4000 2000 1600 1200 800 Mass Spectrum 131 عقل مقلمتململمعلم So base peske 103 M CHO...
Problem 4 IR Spectrum ud 1600 LL 4000 2000 1600 1200 800 Mass Spectrum 131 عقل مقلمتململمعلم So base peske 103 M CHO 280 40 80 120 160 200 240 13C NMR Spectrum M CDO, Rewives DEPT CHẢ CHỊ CHẾ expansion is higher ed proton decoupled 200 160 120 06 (ppm) "H NMR Spectrum (200 MHz, CDCI, solution) expansion 10 9 8 7 2 1 8 (ppm)
Label the spectra and propose a structure for the compound. Compound 5 IR Spectrum Olquid fim...
Label the spectra and propose a structure for the
compound.
Compound 5 IR Spectrum Olquid fim 1740 4000 3000 20 ,1600 1200 300 100% Mass Spectrum M = 150/152 (15) CH,40, CI 240 280 40 80 120 160 200 13C NMR Spectrum (500 M , CDC, son DEPT CH CH CH selvon proton decoupled 200 160 120 80 40 0 8 (ppm) 'H NMR Spectrum (200 MH. COCI, solution 10 9 8 7 6 5 4 3 2 (ppm)
need help elucidating this please IR spectrum 4000 3000 1200 800 2000 V (cm 1600 )...
need help elucidating this please
IR spectrum 4000 3000 1200 800 2000 V (cm 1600 ) Mass Spectrum No significant UV absorption above 220 mm 101 M 40 80 120 160 200 240 280 13C NMR Spectrum (1000MCDC, DEPT CHICH.CH proton decoupled 200 160 120 80 40 0 (ppm) 'H NMR Spectrum (400 MHz, CDCI, solution) expansion 10 PPM 10 9 8 7 6 5 4 3 2 1 8 (ppm)
Draw the organic structure that is represented by the
following spectra:
R Spectrum Mass Spectrum absorption above 220 m 40 80 120 200 240 200 C NMR Spectrum 200 160 120 80 H NMR Spectum 10 る(ppm) Problem 71 Loc 2122 of 3148 74%
Problem 19 IR Spectrum 2000 1600 1200 800 100 Mass Spectrum No significant UV absorption above 220 nm 40 M+ 147149 40 80 120 160 200 240 280 m/e 3C NMR Spectrum (100 MHE, CDC, solution) proton decoupled 200 160 120 40 0 8(ppm) H NMR Spectrum 22 ppm 8 5 2 δ(ppm)
Find the structure
IR Spectrum quid 4000 3000 2000 V (cm 1600 ) 1200 800 0.0 Mass Spectrum 0.5t of base peak UV spectrum 1.075 mg/10ms path length: 0.10 cm solvent: ethanol CH100 280 1.5 40 80 120 160 m/e 200 240 200 250 cm 300 13C NMR Spectrum (1250 MHZ COCI, solution) DEPT CH CH CH! proton decoupled 200160120 80 40 08 (ppm) TH NMR Spectrum (600 MHz, CDCI, solution) expansions expansion pom 10 9 8 7 6 5...
Problem 50 IR Spectrum 2000 1600 1200 800 V (cm) Mass Spectrum 80 No significant UV absorption above 220 nm 60 40 80 120 160 200 240 280 m/e 13C NMR Spectrum proton decoupled 200 160 120 40 0 8(ppm) H NMR Spectrum (200 봐な. CDC, solution) 4.0 10 δ (ppm)
Label the spectra and propose a structure for the compound.
Compound 2 R Spectrum Bedie 3400 1720 4000 3000 2004 1600 vomi) 1200 800 183 Mass Spectrum Softbase de UV Spectrum . mar 253 nm 109,96 26) mas 250 nm 109,2.7) 2 mar 284 m 109,0 2.5) M -220N) CH2O 280 40 80 120 160 200 240 13C NMR Spectrum (100 . CDC, DEPT CH Chicht protondeco 200 160 120 80 400 (ppm) 'H NVR Spectrum (400MCDO, Exchanges wayo Exchanges...
Attached are four spectra for isomer with the MF=
c12h14o4. Determine the structure for each molecule and draw them
below.
problem 63 IR Spectrum (CCI, solution) 1765 4000 3000 1200 800 2000 V (cm ) Mass Spectrum UV Spectrum & 8 8 g 8 of base 2 mar 269 nm (10910€ 2.7) humax 263 nm (10910 2.7) M -222 (< 1) 169 sahent: methanol 8 C12H1404 240 280 40 80 120 160 200 13C NMR Spectrum (50.0 MHz, COCI, solution)...
determine the compound structure based on the
spectrums. please explain.
IR Spectrum liquid rim) 1600 1200 800 4000 3000 2000 V (cm') 100 콩2 No significant LV absorption above 220 nm 40 3 C6H1004 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (S0.0 MH, CDC, solution) proton decoupled 40 0 δ(ppm) 200 160 120 80 H NMR Spectrum (200 MHz, CDCi solution) 10 9 8 76 5 4 3 2 1 0 8 (ppm)
Problem 4 IR Spectrum ud 1600 LL 4000 2000 1600 1200 800 Mass Spectrum 131 عقل مقلمتململمعلم So base peske 103 M CHO 280 40 80 120 160 200 240 13C NMR Spectrum M CDO, Rewives DEPT CHẢ CHỊ CHẾ expansion is higher ed proton decoupled 200 160 120 06 (ppm) "H NMR Spectrum (200 MHz, CDCI, solution) expansion 10 9 8 7 2 1 8 (ppm)
Label the spectra and propose a structure for the
compound.
Compound 5 IR Spectrum Olquid fim 1740 4000 3000 20 ,1600 1200 300 100% Mass Spectrum M = 150/152 (15) CH,40, CI 240 280 40 80 120 160 200 13C NMR Spectrum (500 M , CDC, son DEPT CH CH CH selvon proton decoupled 200 160 120 80 40 0 8 (ppm) 'H NMR Spectrum (200 MH. COCI, solution 10 9 8 7 6 5 4 3 2 (ppm)
need help elucidating this please
IR spectrum 4000 3000 1200 800 2000 V (cm 1600 ) Mass Spectrum No significant UV absorption above 220 mm 101 M 40 80 120 160 200 240 280 13C NMR Spectrum (1000MCDC, DEPT CHICH.CH proton decoupled 200 160 120 80 40 0 (ppm) 'H NMR Spectrum (400 MHz, CDCI, solution) expansion 10 PPM 10 9 8 7 6 5 4 3 2 1 8 (ppm)
Most questions answered within 3 hours.
-
A hot-air balloon is descending with a velocity of (−2.00m/s)y^.
A champagne bottle is opened to...
asked 11 minutes ago -
1. When a nearsighted person looks at an object that is in the
distance with their...
asked 1 hour ago -
QUESTION 8
Both of these statements will store the same value in the
variable $number
$number...
asked 1 hour ago -
The price of 1 lb of potatoes is $1.75. If all the potatoes sold
today at...
asked 2 hours ago -
Garcia Company issues 20.00%, 15-year bonds with a par value of
$470,000 and semiannual interest payments....
asked 2 hours ago -
In C++ Programming, Try using loops only.
This lab demonstrates the use of the While Loop...
asked 3 hours ago -
Effect of DCMU and sodium azide on Chlamydomonas? We did an
experiment where we had Chlamydomonas...
asked 4 hours ago -
1a) According to the ideal gas law, _______________.
a. a gas has infinite volume at absolute...
asked 5 hours ago -
Oakdale Fashions, Inc. had $245,000 in 2018 taxable income.
Using the tax schedule in Table 2.3...
asked 6 hours ago -
The marketing class at CSUS had an average score of 150. An
educational analyst determined that...
asked 7 hours ago -
Justin Case has purchased a $250 000 home by putting 20 % down
and taking out...
asked 7 hours ago -
1. In a labor market, marginal cost for a firm is
____________.
a. recruiting cost
b....
asked 8 hours ago