determine the compound structure based on the spectrums. please explain.
determine the compound structure based on the spectrums. please explain. IR Spectrum liquid rim) 1600 1200...
Problem 79 4000 3000 2000 1600 1200 800 V (cm) Mass Specrum uv Spectrum 100 80 60 40t 3 20 max 260 nm (logroE 2.5) 91 solvent: methanol C11H16 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDC, solution) proton decoupled 200 160 120 40 0 δ(ppm) H NMR Spectrum (200 MHz, CDci, solution) 7.5 7.0 ppm
Find the compounds using NMR and IR: Problem 85 IR Spectrum (liquid fiim) 1720 1600 2000 v (cm) 800 3000 1200 4000 100 Mass Spectrum 73 140 138 80 No significant UV 60 115 absorption above 220 nm 40 M 194/196 (1% ) 20 CeH1102Br 120 160 200 240 280 40 80 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH, Cн, сн! solvent proton decoupled 8 (ppm) 160 120 40 200 80 H NMR Spectrum (200 MHz, CDCI,...
Find the compounds using IR and NMR: Problem 25 2251 IR Spectrum (liquid film) 800 1600 1200 4000 3000 2000 v (cm) 100 Mass Spectrum M 117 80 77 60 91 40 20 CgH7N 200 80 120 160 240 280 40 m/e expansion 13C NMR Spectrum (100.0 MHz, CDCI, solution) 130 129 ppm DEPT CH Cн,! сн! expansion 130 129 ppm solvent proton decoupled (ppm) 40 200 160 120 80 H NMR Spectrum (400 MHz. CDCI, solution) TMS 10 7...
Fall 2019 Problem 5 IR Spectrum (iquid fim) 1715 4000 3000 2000 V (cm) 1600 1200 800 100 44 Mass Spectrum 80 60 58 20 M. 86 C5H100 280 40 240 80 200 120 160 13C NMR Spectrum (20.0 MHz, CDCI, solution) -CH3 C-H proton decoupled TMS CH solvent ul 5 (ppm) 40 80 120 160 200 H NMR Spectrum (100 MHz, CDC, solution) expansion of 400 MHz spectrum 20 Hz TMS 0.99 ppm 2.21 2.31 9.75 2 3 6...
Label spectra and propose a structure for the compound. Compound 1 IR Spectrum liquid mi 4000 3000 2000 1600 1200 1200 V on Mass Spectrum UV Spectrum 2. max 252 mm (10910622) 2. max 257 nm (log, 2.3) 2 mar 262 nm (10910€ 2.2) 2. max 254 nm (1090€ 2.2) 2.mex 268 nm logo 2.0) solvent thanol M 150 Coto2 40 80 240 120 m 200 280 160 /e 13C NMR Spectrum (100 M-2. CDC, solution ansion DEPT CH chut...
need help elucidating this please IR spectrum 4000 3000 1200 800 2000 V (cm 1600 ) Mass Spectrum No significant UV absorption above 220 mm 101 M 40 80 120 160 200 240 280 13C NMR Spectrum (1000MCDC, DEPT CHICH.CH proton decoupled 200 160 120 80 40 0 (ppm) 'H NMR Spectrum (400 MHz, CDCI, solution) expansion 10 PPM 10 9 8 7 6 5 4 3 2 1 8 (ppm)
determine the compound structure based on the spectrums 2114 3296 R Spectrum 4000 2000 1 V (cm) 3000 1600 1200 100 Mass Spectrum Du)-26)12-9-しキ N° significant uv absorption abave 220 nm 40 M-83 CsHgN 40 80 120 160 200 240 280 m/e 13 C NMR Spectrum (100 0 MHz, CDCi, solution) proton decoupied δ(ppm) 0 40 80 120 160 200 H NMR Spectrum (400 MHE, CDci, soudon) with 2H 2H 1H 2H 2H 1.5 8 (ppm) 10 9 8 7...
Problem 4 IR Spectrum ud 1600 LL 4000 2000 1600 1200 800 Mass Spectrum 131 عقل مقلمتململمعلم So base peske 103 M CHO 280 40 80 120 160 200 240 13C NMR Spectrum M CDO, Rewives DEPT CHẢ CHỊ CHẾ expansion is higher ed proton decoupled 200 160 120 06 (ppm) "H NMR Spectrum (200 MHz, CDCI, solution) expansion 10 9 8 7 2 1 8 (ppm)
Problem 50 IR Spectrum 2000 1600 1200 800 V (cm) Mass Spectrum 80 No significant UV absorption above 220 nm 60 40 80 120 160 200 240 280 m/e 13C NMR Spectrum proton decoupled 200 160 120 40 0 8(ppm) H NMR Spectrum (200 봐な. CDC, solution) 4.0 10 δ (ppm)
do the spec problem Problem 9 IR Spectrum (kuid im) 0.0 800 1600 1200 2000 V (cm) 3000 4000 Mass Spectrum 0.5F 100 80 60 UV spectrum 1,0 77 107 5.815 mg/ 10 mls path length: 1.00 cm solvent: ethanel M 122 20E 1.5 300 350 250 200 200 280 240 120 160 40 80 (nm) m/e 13C NMR Spectrum Aath (20.0 MHz, CDCI, solution) expansion x5 off-resonance decoupled proton decoupled 200 160 120 80 8 (ppm) 40 0 1H...