Question

Define a single dimensional array of size 6. Populate the array by a double nested loop using i and j as the loop variables. Index the array with i*2+j, and fill in the array with the value i + j. c programming

Answer 1

C CODE :

#include <stdio.h>

int main()
{
int array[6],temp=0,i,j,k; // initializing local variables and array with size 6
for(i = 0;;) // outer loop
{
for(j=0;j<6;j++) // inner loop
{
   temp = (i*2)+j; // logic
   array[temp] = i+j;
}
break;
}
printf("array elements are :"); // displaying resultant array
for(k=0;k<6;k++)
   {
   printf("\n %d",array[k]);
   }
return 0;
}

OUTPUT :

*New Project-20160908 白白root +《 compile ! Execute ! > Share Code main.cx 1 #include <stdio.h> main.c 3 int main() 4 int array [6],temp-0,i,j, k; // initializing local variables and array with size 6 for(i e) outer loop for(j-0汀(6汀++) // inner loop 10 temp (i 2)+; II logic array [temp] i+j; = 12 13 14 15 printf ("array elements are ) II displaying resultant array 16 17 ▼ 18 19 20 21 break for(k-0;k<6;k++) printf("\n %d " , array [k]); return 0 23 24 25 Terminal sh-4.3$ gcc o main *. C sh-4·35 main array elements are: 2 3 4 5sh 4.3$