A 4.00 m length of light nylon cord is wound around a uniform cylindrical spool of...
A 4.00 m length of light nylon cord is wound around a uniform cylindrical spool of radius 0.500 m and mass 1.00 kg. The spool is mounted on a frictionless axle and is initially at rest. The cord is pulled from the spool with a constant acceleration of magnitude 2.90 m/s2. How much work has been done on the spool when it reaches an angular speed of 7.30 rad/s? (The answer is not 0.9125 J)
Homework Answers
Moment of Inertia of cyclindrical spool,
I = 0.5*m*r^2
= 0.5*1*(0.5)^2
=0.125 Kg.m^2
w = change in rotational kinetic energy
= 0.5*I*wf^2
= 0.5*(0.125)*(7.3)^2
= 3.331 J
Answer: 3.331 J
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A 4.00 m length of light nylon cord is wound around a uniform
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• 7.4/11.11 points Previous Answers SerPSE9 10.P.067. My Notes Ask Your Teacher A 4.00-m length of light nylon cord is wound around a uniform cylindrical spool of radius 0.500 m and mass 1.00 kg. The spool is mounted on a frictionless axle and is initially at rest. The cordis pulled from the spool with a constant acceleration of magnitude 2.72 m/s2 (a) How much work has been done on the spool when it reaches an angular speed of 6.65 rad/s?...
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