Steve invest 10,000 today for 12 years with an interest rate of 12.5 %
GIVEN:
Principal investment at the beginning = $10000
Interest rate compounded quarterly = 12.5%/4 = 0.125/4 = 0.03125
Double the investment, Amount = $20000.
Now, we need to calculate that how long it will take to double the investment.
Let our Desired Future value = $20000
Formula,
Future value (FV) = P(1+i)n
where P - Principal investment = $10000, i - interest rate = 0.03125
we need to calculate 'n' - no. of quarterly periods
=> $20000 = $10000(1+0.03125)n
=> (1.03125)n = $20000/$10000
=> (1.03125)n = 2
we can written 2 as (1.03125)24
=> (1.03125)n = (1.03125)24
Applying mathematical rule that bases are equal, so the powers are also equal.
=> No. of quarterly periods (n) = 24
Therefore,
No. Of years = 24/4 = 6 years
IT TAKES 6 YEARS TO DOUBLE THE INVESTMENT IF COMPOUNDED QUARTERLY
_____×_____
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