Question

Complete the table Molarity Solute Mass of solute Moles of solute Volume of solution of solution MgSO4 0.638 YLE 30.0 mL NaOH 115.0 ml 1.45 M CH3OH 15.5 g 0.520 M

Answer 1

litre of molarity- Molarity = no- of moles of solute present in one - the solution is called Molarity number of moles of of solute volume (2) Mass of solute number of moles= molar mass of of solute solute l Molarity Mass of solute - Molar mass of solute " volume (4) 1000 Mass of solute Molarity a Molar mass of solute volume (mi)

First 706 Mass of Mosqu = 0.63888. molar mass of maso = 120.378 lmol moles of mass of Mg so 0.638 120:37 Moso - molar mass of mgs4 moles of Mgsą = 0.0053 moles . volumea 30 ml moles of masa x1000 Molarity = - volume (mi) 0.0053 x1000 30

second 70w molarity of NaOH = moles of Naot X1000 volume (ml). moles of waoH + 1000 1.45= - 115 moles of NaOH = 0.16875 mole molar mass of Nao ha 40g1mol moles of nagha- Mass of Nadhi rolar mass of Nagh Naoh Mass of 0.16675= 40 0.16675x40= 6.6788 NaOH = Mass of

Third row mass of CH ₂ OH = 15:588 Molar mass of CH, OH = 32glmol moles of mass of eH₂oH 15.5 0.484375 mol 32 CH₃OH - molarmass of CH₂OH moles of CH₂OH X1000 volume ani) molqority z 0.52 = 0.484375X1000 1 volume 0.484375 x1000 volume 0.52 931.49 mi Rate please