Molarity(m)=Moles (mol) of solute/Liters (L) of solution
Molarity of standard NaOH from bottle = 0.1005 M
Molarity of NaOH added in titration (mL) = 10.47 mL
1. Moles of NaOH added in titration ______
Molarity(M)=Moles (mol) of solute/Liters (L)
It is the formula
We are given with
Molarity = 01005 M
Volume = 10.47 mL
Converting mL to L
=0.01047 L
Volume = 0.01047 L
Plug in the values in the formula
Multiply both sides with 0.01045 L
0.001050 = mol
Therefore, moles of NaOH in solution = 0.001050 mol = 1.050 x 10-3 mol
Molarity(m)=Moles (mol) of solute/Liters (L) of solution Molarity of standard NaOH from bottle = 0.1005 M...
The units for molarity, M, are grams of solute Liters of solutiorn moles of solution Liters of solution moles of solute grams of solution moles of solute Liters of solution O
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Molarity of the standard solution of sodium hydroxide = 0.11667 mol/L. Volumes of NaOH(aq): Rough titration First titration Second titration Third titration Fourth titration Final burette reading: (mL) 26.33 41.98 25.89 42.57 28.81 Initial burette reading: (mL) 11.13 27.01 10.88 27.36 13.79 Volume of NaOH(aq) titrated: (mL) 1. When NaOH(aq) was added to H2SO4(aq), why was a precipitate NOT formed? _______________________________________________________________________ At the end point of the titration, what substance changed its colour? ________________ Define a dilution: _______________________________________________________ Give a...
Find:
Moles of NaOH (mol)
Volume of NaOH (L)
Molarity of NaOH mol/L
Average Molarity
Deviation from mean
Average deviation
Percent Relative Average Deviation
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Exp 9 titration of vinegar procedure b
molarity of NaOH = .0859
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