The solubility product of calcium fluoride (CaF2) is 3x10^-11. If water contains 250 mg/L calcium, how much fluoride will be soluble?
The solubility product of calcium fluoride (CaF2) is 3x10^-11. If water contains 250 mg/L calcium, how...
(15 pts) The solubility product of calcium fluoride (CaF2) is 3.45 x 10-11 at 25°C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 150 mg/L of calcium?
2) The solubility product for calcium fluoride (CaF2, MW largest 78.1 g/mol) is Kp 4.0 x 10-11 What is the mass of calcium fluoride that can dissolve in 250.0 mL of water? 2) The solubility product for calcium fluoride (CaF2, MW largest 78.1 g/mol) is Kp 4.0 x 10-11 What is the mass of calcium fluoride that can dissolve in 250.0 mL of water?
What is the solubility of CaF2 (calcium fluoride) in... a) ...pure water? b) ...0.4 M caCl2
2. The molar solubility of calcium fluoride in water is 2.1 x 104 moles/L. What is the Ksp of CaF2? a) 3.7 x 10-11 b) 2.14 x 10-4 c) 4.6 x 10 d) 9.8 x 10-12
2. The equilibrium constant for the following reaction is called the "solubility product" of calcium fluoride: CaF2(s) - Cal(aq) + 2F-(ay) K = Kp = 3.2 x 10-11 (a) Write an expression for the equilibrium constant of this reaction in terms of concentrations. Why do you suppose we call this a solubility product instead of a solubility quotient or ratio? (b) Calculate the equilibrium concentrations of Ca2+ and F if excess solid CaF is placed in water. (c) in which...
1. Solid calcium fluoride (CaF2) establishes the following equilibrium in solution: CaF2(s) = Ca2+(aq) + 2F-(aq) Ke = 1.5 x 10-10 A solution initially contains 2.45 g of CaF2. a. In which direction will the reaction move to reach equilibrium? Explain your reasoning b. Calculate the equilibrium concentrations of Ca2+ and F. How much CaF2 (in mg) dissolves in solution? c. Another solution initially contains 2.45 g of CaF2 and 0.0025 M NaF. What are the equilibrium concentrations of Ca2+...
QUESTION 6 (15 points) A) A saturated solution of calcium fluoride CaF2 is found to contain a concentration of fluoride ions [F] = 3.0 x 10-6 M. What is the value of the solubility product of this salt?
1. The molar solubility of Pbly in water is 1.5x10-mol/L. What is the solubility product of Pblz? answer = What is the molar solubility of Pb(OH)2 in a solution that is 0.010 M NaOH? The Ksp for Pb(OH)2 is 2.8x10-16 answer = 3. CaF2 dissolves in pure water. If the molar solubility of CaF2 is 2.2x10-4 mol/L, what is the concentration of fluoride in solution at equilibrium? answer
17. Calculate the solubility of calcium fluoride in a 0.035 M sodium fluoride solution. Some important information is given below: ▪ NaF will ionize completely, and the reaction is: NaF (aq) → Na+ (aq) + F− (aq) ▪ The calcium fluoride equilibrium reaction is: CaF2 (s) → Ca+2 (aq) + 2F−1 (aq) ▪ For CaF2 (s), Ksp is 4.0 × 10−11 ▪ Na+ (aq) is a spectator ion; The F− (aq) is the common ion.
5. The molar solubility for calcium fluoride, CaF2, is 2.0 x 10' M at 25°C. Calculate the solubility product constant for calcium fluoride a. 1.4 x 102 b. 8.0 x 10-8 c. 1.6 x 10-11 d. 3.2 x 10" e. 4.2 x 10-24 e. None of these statements is liue. 15. Which of the following statements regarding complex ions is true? a. Complex ions are formed of a metal ion and a ligand. b. The metal ion is a Lewis...