Question

H03.5 An open container of oil rests on the flatbed of a truck that is traveling along a horizontal road at 55 mi/hr. As the truck slows uniformly to a complete stop in 5 s, what will be the slope of the oil surface during the period of constant deceleration?

just explain in the second Q

Answer 1

Fr. Reaction force in horizontal Fy: Reaction force in vertical FHk Fx Wwater vollume of water over gate wake = 11 R&L Vandex > [ 2264) 12.566m3 In the shaded Region, weight of waks Elennene W Wales = water water = (9.8 kW/m?) (12.56803) - 123.146 kW Horizontal component of folle Enerbed by water FH = "water Aah Where A = Ral= 224 28m2 n = 6-2 = 5m. Fue = (9.8) (8) (5) = 392 KN

The vertical force Enerted by the water Aboles gate Fu = V water CH-R) A A = R&L = 8m² fu= (908) (6-2) (8) = 313.6 kN : 436.746 kW from Equilibrium. Efy zo : Fy - W water -fu=0 Fy = 436.746 kW] & Fx = 0: En = 8392 kN) Fresulfent = E + Fy IF AN- Fresadart All the forces on casued surface are acting peopendicular! to sissale . Resultant must pass through the intersection of all these forces which is at poine A.