Question

6. A plate with width of 400mm and thickness of 12mm is to be connected to a plate of the same width and thickness by 34mm diameter bolts as shown in the figure. The holes are 2mm larger than the bolt diameter. The plate is A36 steel with yield strength Fy=248 MPa. Allowable tensile stress is 0.60Fy. It is required to determine the value of "b" so that the net width along bolts 1-2-3-4 is equal to the net width along bolts 1-2-4. Which of the following most nearly gives the value of P so that the allowable tensile stress on net area will not be exceeded? points: 1 60 b 10 11100 20 hoo - 400mm 30 17100 150 519 KN 529 KN 539 KN 549 KN

Answer 1

Net width= Gross width - Choleste- solution! s² 49 1502 t + 602 t + Net coidth C1-2-4) = net width (1-2-3-4) 400-3 (34+2) + 602 +(150-b)? 400-4(3472) 4(100) 4(200) 52 4(100) 4 (100) ulioo) , b=19-71 Consideuin path 1-2-3-yor path 1-2 on = 400-3(34+2)+ 602 (150 - 19.71)? 4(100) 4 (100) on=322.22 mm path 1-2-3 19.71 Wn: 400 (34+2) u(100) 4(100) Ons 301,97 mm wna Critical net alea - 30). 97 (12)=3624mm? P = 3624x[0.61248)]= 539.2 kw p=539 KN 2 Considering , ? It 602 3 P