Question

The post is made of Douglas fir and has a diameter of 100 mm. (Figure 1) It is subjected to the load of 20 kN and the soil provides a frictional resistance distributed around the post that is triangular along its sides; that is, it varies from w=0 kN/m at y=0 m to w=10 kN/m at y=2 m. Neglect the weight of the post.

<HW-1 Problem 4.21 Part A The post is made of Douglas fir and has a diameter of 100 mm (Figure 1) It is subjected to the load of 20 kN and the soil provides a frictional resistance distributed around the post that is triangular along its sides, that is, it varies from w 0 kN/m at y 0 m to w = 10 kN/m at y = 2 m Neglect the weight of the post. Detem Expre: F Figure < 1 of 1 > 20 KN - Part E What is Expres 12 kN/m Aramak için buraya yazın DO DOLBY HOME THEATER

Answer 1

20KN Post Given data, For past made - of Douglar for, Dianneler of post = 100 mm - D - 100 mm Given at y=0; w=0kN/m at y= 2m; WC 10 kN/m نکته Now considering the post, 20kW 'W, = Area of force distribution W, = 4x2m x 10 KN) - - wi= 10 kn 2017 ** 2x10=joka L Now considering the entire post, 23 7+ <Fyso → F-20 + wy=0 → F-20 + 10 = 0 1 10 kN/m-W F → F= 10KN 20KN - 6) Considering the internal force free body diagram at y, wz 104 KN 1 Then, het - Wy= Area of force distribution cs Camisedmieniformly valying FCG)

e's what Choy) logo Now HEFyzo , - Wilts respec SA/B = 1 Fly Day JAE Lm -- 20 + log? - F(y) = 0 → Fly) = 10 y2– 20 > FG) -32.5°-203-60 Displacement of A with respect to B,+ 546 = Septembre | aytao)dy AE (EN) - 20y) Sklo - Part [ 70 - 40) = -63.333 kW-m) 4 = cross sectional area of post = 2 02-2017 → A = 7.85398 mm For Douglas fer, E = 13.1x109 pa = 13. 18109 W/m2 SAM = -33.3338103 = -3.23976x104m 103(7.85398) X (13.18 709) P 8A%) = -0.323946 mm / cHeren ne rregative sign indicates that A moves towards the end B. AE CamScanner