Question

Consider the simply supported beam shown in (Figure 1). Suppose that P = 10 kN, w = 5 kN/m. Point D is located just to the left of the 10-kN concentrated load. Follow the sign convention Part A Determine the internal normal force at point C. Express your answer to three significant figures and include the appropriate units. НА ? Nc = Value Units Submit Request Answer Part B Determine the internal shear force at point C. Express your answer to three significant figures and include the appropriate units. Figure μΑ < 1 of 1 > ? Vc = Value Units IP Submit Request Answer w Part C B D Determine the internal moment at point C. Express your answer to three significant figures and include the appropriate units. -1.5 m 1.5 m - 1.5 m 1.5 m- 1 μΑ ?

Answer 1

E Fx = 0 FBD of given dicognoom we Skal Paloka A Af T BY 4. sn + 1.5m 1.5M Toke moment of A, EMA = 0. By x 6 - 10x4.5-($*5*3)*(3*$) - 0. By = 8.75 KN ; Efr 0; Ax = 0 2 Fy *0) Ay+ By - (1x385) -10=0 Ay 11+(7.5) - 8.75 9.75 KN Ay SKOG loka voolue of h wolu h 1.5. Ax < By Ay h=2.5kN/m oot point © 2. Skolo loka E Fy = 0 Ve-( **2.5*1.5) -10 +By = 0 1 Met=1.5 → By = 3.125 KN Vc = Ne=0

Moment about 6 EMC=0 ( Byx4.5) - 1 - 10x3 - { * 2.5x1.5(5x1.5) - Mc 39.375-30 -0.9375 Me = 8.4375 KN- point poi 10KN & Fy = 0 TBY 10 -10 + By MP Vp V = 1.25KN & Fy=0 V + By Vo = - 8.75 kn Efx = 0 No=0 Moment about ① EMD=0 By x1-5 - Moo Mo = 13.125kNom
please comment below for any queries... thank you....