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If Neptune originally formed at 20 AU and then migrated to its present distance of 30...

If Neptune originally formed at 20 AU and then migrated to its present distance of 30 AU, how much was Neptune's orbital speed reduced during the migration?

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Answer #1

Intial distance of Neptune = R = 20 AU ; Present distance = R' = 30 AU

Let V be the initial orbital speed and V' be the final.

We know that, orbital speed is given by:

V = sqrt (GM/R)

V = sqrt (GM/20AU)

V' = sqrt (GM/30AU)

dividing V'/V

V'/V = [sqrt(GM) / sqrt (30 AU)] x [sqrt(20 AU) / sqrt(GM)]

V'/V = sqrt (20/30) = 0.816

V' = 0.816 V

Hence, during the migration the orbital speed of neptune got reduced by a factor of 0.816 of its original speed.

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