A.
For isobaric process,
energy transferred to the gas is given by:
Q = n*Cp*dT
n = number of moles = 2
Cp = Molar specific heat at constant pressure = 20.79 J/mol-K
dT = 420 - 300 = 120 K
So,
Q = 2*20.79*120 = 4989.6 J
Part B.
Change in internal energy is given by:
dU = n*Cv*dT
Cv = Cp - R = 20.79 - 8.314 = 12.476
So,
dU = 2*12.476*120 = 2994.24 J
Part C.
Using first law of thermodynamics
dQ = dU + W
W = dQ - dU
W = 4989.6 - 2994.24
W = 1995.36 J = Work-done on the gas
Part D.
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