Question

1. Two cars, a Toyota Yaris and a Jeep, are traveling in the same Jirection, although the Yaris is 186 m behind the Jeep. The speed of the aris is 24.4 m/s and the speed of the Jeep is 18.6 m/s. How much time oes it take for the Yaris to catch the Jeep? [ Hint: What must be true bout the displacement of the two cars when they meet?]

Answer 1

Toyota deep '186m Vy = 24.4 m/s , V = 18.6 misec Let in time t, this, Toyota catch up, Jeep geep covered x metres, in has to cover (186+1) m to

in timet. Toyota moves (186th) m & Jeep um. Displacemed) Distance by Toyotal = 24:4x7 - 0 Displacemos / Distance by Jeep - 18.6x+ at meeting point x= 18.68t (x+186-24.4 t. ( 186 xt+18 6 = 24 ft. 186=(24.4-1816) t. 186 = 518xt It -32.o6seat +

(a) a= -4 = 27.3-1714 10 [a= 0.99 M/sec? Distance covered in this time V= 27.3, u=1714m v² = 4²+2 as t=10 sec ac0'99 (27.3) 117.4)2X0-99XS 745:29=302.76 +1.9885.

745.29-302.76 =s 1.98 [22315 m.