Question

two cars are traveling on the parkway with different speeds but the same directions. The slower car is traveling at 25 m/s and the faster car is traveling at 35 m/s. If the slower car starts 100 m ahead of the faster car, when and where will the faster car pass the slower car?

Determine when and where the faster car passes the slower car.

Answer 1

Difference in distance =100m

Difference in speed = 35m/s-25m/s =10m/s

Time taken by faster car to cross slower car = $\frac{Distance}{Speed} =\frac{100}{10} =10s$

So, the faster car will take 10 seconds to pass the slower car.