MC Question:
With Chi-square test the expected values reflect the empirical manifestation of:
(a) The alternative hypothesis
(b) the null hypothesis
(c) the sampling distribution
(d) a random distribution
MC Question: With Chi-square test the expected values reflect the empirical manifestation of: (a) The alternative...
Question 1 In a chi -square test of independence , the null hypothesis states that-----------. a. the two variables of interest are related in the population. b. the column frequencies equal the row frequencies c. the sum of the and the column frequencies equal the total frequency d. the two variables of interest are unrelated in the population Question 2 A survey asked people whether they identified as a morning person, night person, or had no preference. a. 270 replied...
A distribution and the observed frequencies of the values of a variable from a simple random sample of the population are provided below. Use the chi-square goodness-of-fit test to decide, at the specified significance level, whether the distribution of the variable differs from the given distribution Distribution: 0.1875, 0.1875, Observed frequencies: 16, 20, 24, 36 Significance level 0.05 0.3125, 0.3125 Determine the null and alternative hypotheses. Choose the correct answer below. OA. H: The distribution of the variable differs from...
a) true b) false 42. For a chi-square distributed random variable with 10 degrees of freedom and a level of sigpificanoe computed value of the test statistics is 16.857. This will lead us to reject the null hypothesis. a) true b) false 43. A chi-square goodness-of-fit test is always conducted as: a. a lower-tail test b. an upper-tail test d. either a lower tail or upper tail test e. a two-tail test 44. A left-tailed area in the chi-square distribution...
If the chi-square test is χ2(4, N = 71) = 3.472, then we ______. a. fail to reject the null hypothesis b. reject the null hypothesis c. reject the one-tailed null hypothesis d. reject the alternative hypothesis
How to write a Null Hypothesis and Alternative Hypothesis for two independent nominal Chi Square test. Example variable: 1. Currently have COPD 2. Visits to the Doctors
QUESTION 58 The chi-square test of independence does not allow us to state that one variable causes a change in another variable when the null hypothesis is rejected. True False QUESTION 59 When performing a hypothesis test to compare two or more population proportions, the expected frequencies must always be integer values. True False QUESTION 60
When we carry out a chi-square goodness-of-fit test for a normal distribution, the null hypothesis states that the population: a) does not have a normal distribution. b) has a normal distribution. c) has a chi-square distribution. d) does not have a chi-square distribution. e) has k − 3 degrees of freedom.
Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant difference between what we would expect results to be, and what the actual results were. That is, expected vs. observed. Use alpha = .05 Listed below are data from a survey conducted recently where Males and Females responded to their happiness with their supervisor (this is fictitious data). Response Male Female Total Not at all 23 25 48 Somewhat 13 22 35 Very 26 16 42...
Given the following observed phenotypic ratios, calculate the expected phenotypic ratios and chi square values. Then evaluate the chi square value using a chi square table to accept or reject the null hypothesis at a P value of 0.05. Place the appropriate boxes in correct position in the table
The Chi-square test is often used to test if different ratios are the same, for example to see if a trait is controlled by one or many genes. Here we would like you to see if there the ratio is equal to the 3:1 ratio which would mean the trait is controlled by a single gene, for the gene shrunken2 which makes corn sweet. 4. Class Expected Frequency Round 290 300 Shrunken2 110 100 a. What is the null hypothesis?...