Question

For the decomposition of ammonia on a platinum surface at 856 °C 2 NH3-N2 + 3 H2 the average rate of disappearance of NH; over the time period from t = 0 stot - 852 s is found to be 1.50~10 Ms!. The average rate of formation of H, over the same time period is Ms! Submit Answer Try Another Version 10 item attempts remaining Visited Prev

Answer 1

According to the rate kinetics

-1/2 {d[NH3] / dt} = d[N2]/dt = 1/3 {d[H2]/dt} ...................................(negative because of the consumption )

Given that avarage rate of NH3 =1.50*10^-6

Then rate of formation of H2 =

1/2 {d[NH3] / dt} = 1/3 {d[H2]/dt}

=>d[H2]/dt = 3/2  {d[NH3] / dt}

=> d[H2]/dt = 3/2 ( 1.50 * 10 ^-6)

=> d[H2]/dt = 2.25*10^-6 MS^-1

So the rate of formation of H2 = 2.25*10^-6 Ms^-1

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