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8.3.24 EQuestion Help Construct a 90% confidence interval usang the nequality d-cYn <pd < d + tc To test the effec veness of a new drug that is reported o increase the number of hours of sleep patients get during , the night, researchers randomly select 13 patients and record the number of hours of sleep each gets with and without the new drug. Patient Sleep without the drug 2.8 4.9 4.2 4.8 3.2 2.1 3.4 2.5 2.8 4.8 3.4 |3.7 4.3 1 2 3 45 6789 10 1112 13 Sleep using the drug 4.0 66 5.9 73 5.6 3 The confidence interval is | | < ?0 Type an integer or a decimal. Round to two decimal places as needed.)

math   Statistics-And-Probability   
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S. No 1 2 with 4 6.6 without difference(d)=x1-x2 1.2 1.7 1.7 2.5 1.440000 2.890000 2.890000 6.250000 5.760000 1.960000 6.250000 1.960000 0.360000 1.210000 1.440000 6.760000 5.760000 2d2-44.93 4.9 4 7.3 4.8 3.2 2.1 3.5 1.4 2.5 1.4 0.6 3.9 2.5 10 4.8 4.6 1.2 2.6 2.4 2d 22.7 1.746 3.7 12 13 6.7 total mean dbar- degree of freedom -n-1 Std deviaiton Sp V(Ed2-(2d)2/n)/(n-1) std error-SeSp/Vn - 12.000 0.664 0.184 for 90% CI; and 12 degree of freedom, value oft- therefore confidence interval- margin of errror std error= lower confidence limit upper confidence limit 1.782 sample mean -/+t*std error 0.328 1.42 2.07

from above 90% Confidence interval =1.42 < \mu d <2.07

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