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Two horizontal forces act on a 5.6 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy

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kt Given, Mass of the block, m= 5.6 5.6 kg. E = (6î + 10 ŷ, N; F2 = (-6ît q ĝ, N. So, Resultant force on blocks h = h + 5 = (

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