Question

92757477 lectrostatics Part oblem 20.17 8 of 12 Part A Constant A small glass bead has been charged to +20 C what is thethe acceleraton of a proton th.is 15can ton te ce ter or nebear? iput posove value "me negative t is directed away from the bead eletatin tsdeeded toward the bead and Express your answer to two significant figures and include the appropriate units e Units Part B Express your assee. to two sgndcast figures mc opriate unns.

Answer 1

Small glass heat charge = + 20 mc charge on proton = 1.60 times 10^-19 c two charge particle so they applied an electrostatic force on each other in opposite direction force given as F = 1/4 pi epsilon_0 Q_1 Q_2/r^2 radiance Q_1 = 20 mc Q_2 = + 1.60 times 10^-19 c r = 1.5 cm F = 9 times 10^9 times (20 times 10^-3) times (1.60 times 10^-19)/(1.5 times 10^-2)^2 N F = 1.336 times 10^-7 N 1/4 pi epsilon_0 = 9 times 10^9 both charge is positive so direction of force is way from them q_c = Force/mass = 1.336 times 10^-7/1.672 times 10^-27 = 0.799 times 10^20 m/kc^2 charge on electron is -1.602 times 10^-22 so same magnitude as part A F = 1.336 times 10^-7 N but direction of force is towards each other a_cc = 1.336 times 10^-7/9.1 times 10^-31 = 1.468 times 10^27 m/sec^2