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Problem 2. (20 points) How much needs to be cleared on the inside of the curve for visibility along a four-lane highway with
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Answer #1

Given,

Design Speed, V = 60 mph = 88 ft/s

Design superelevation, e = 6.8%

Four-lane highway

Lane width = 12 ft

S = Vt + V​​​​​​2/2a = 88 * 2.5 + 882/(2*11.2) = 220 + 345.7 = 565.7 ~ 570 ft

R = V​​​​​​2/g * (e + f) = 882/32.2 * (0.068 + 0.12) = 1279.24 ~ 1280 ft

Distance from centreline of roadway to the centreline of inside lane, d = 12 ft

Distance cleared from inside of the curve:

m=R-(R- d)cos 1805 27 (R -d)

m - 1980 m = 1280 - (1280 – 12)cos (1990 191 180 * 570 27 (1280 – 12)m = 1280 - 1236.07 = 43.93 ~ 44 ft

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