Question

Daily high temperatures in St. Louis for the last week were as follows: 92, 91, 94, 94, 96, 86, 90 (yesterday). a) The high temperature for today using a 3-day moving average = 90.67 degrees (round your response to one decimal place) b) The high temperature for today using a 2-day moving average = 88 degrees (round your response to one decimal place). c) The mean absolute deviation based on a 2-day moving average = 3.2 degrees (round your response to one decimal place). degrees d) The mean squared error for the 2-day moving average = (round your response to one decimal place).

Answer 1

Answer: According to given data lerror Day Temprature 3DMA lerror? 1 92 2 91 94 4 94 (92+91+94)/3 92.3 1,7 2,89 = 5 96 (91+94+94)/3 93.0 3.0 9.0 75.69 86 (94+94+96)/3 94.7 8,7 4.0 7 90 (94+96+86)/3 = 92.0 2.0 (96+86+90)/3 90.7 8 MAD Average of lerrorl values (1.7+3.0+8.7+2.0)/4 3.9 MSE Average of lerror2 values (2.89+9.0+75.69+4.0)/3 30.5 error Day Temprature 2DMA lerror2 92 1 2 91 94 (92+91)/2 91.5 2,5 6,25 94 (91+94)/2 92.5 1,5 2.25 5 96 (94+94)/2 94.0 2.0 4.0 (94+96)/2 95.0 86 9.0 81 7 90 (96+86)/2 91.0 1.0 1,0 (86+90)/2 88.0 MAD Average of lerrorl values (2.5+1.5+2.0+9.0+1.0)/5= 3.2 MSE Average of lerror2 values (6.25+2.25+4.0+81+1.0)/4 23.6 = st LC C

a) The high temperature for today using a 3-day moving average 90.7 b) The high temperature for today using a 2-day moving average 88 c) The mean absolute deviation based on a 2-day moving average 3.2 d) The mean squared error for the 2-day moving average 23.6