(6)
Here Al is getting oxidized and Cu is getting reduced.
E0cell = Eoxid + Ered = 1.662 + 0.337 = 1.999 V
(b)
False.
Because E0cell > 0 which means cell reaction is spontanoeus.
Determine the standard cell potential (in volts) at 25 degree C for the following reaction. You...
In a galvanic cell, a spontaneous redox reaction occurs. However the reactants are separated such that the transfer of electrons is forced to occur across a wire. The resulting electricity is measured in volts (V) and is the sum of the potentials of the oxidation and reduction half-reactions: E^o cell = E^o red + E^o ox By reversing the reduction half-reactions, you get the corresponding oxidation half-reaction, for which E^o ox has the opposite sign of E^o red You can...
Given the measured cell potential, E_cell, is -0.3657 V at 25 degree C in the following cell, calculate the H^+ concentration Pt (s)|H_2(g, 0.801 atm)|H^+ (aq, ? M)||Cd^2+ (aq, 1.00 M)|Cd (s) The balanced reduction half-reactions for the cell, and their respective standard reduction potential values, E degree, are as follows. 2H^+ (aq) + 2e^- rightarrow H_2 (g) E degree = 0.00 V Cd^2+ (aq) + 2e^- rightarrow Cd (s) E degree = -0.403 V [H^+] =
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Calculate the cell potential for the following reaction as written at 25.00 degree C. given that [Cr^2+] = 0.893 M and [Ni^2+] = 0.0110 M. Standard reduction potentials can be found here. Cr(s)+Ni^2+(aq) Cr^2+(aq)+Ni(s)
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use tabulated standard electrode potential to calculate the standard cell potential for the reaction occurring in an electrochemical cell at 25 C. (The equation is balanced.) 3Ni^2+(aq)+2Cr(s)--->3Ni(s)2Cr^3+(aq) Express your answer to two significant figures and include the appropriate units. em 26 E (V) -0.45 -0.50 -0.73 -0.76 -1.18 Standard reduction half-cell potentials at 25°C Half-reaction E° (V) Half-reaction Aul+ (aq) + 3e +Au(s) 1.50 Fe2+ (aq) + 2eFe(s) Ag+ (aq) +e-Ag(s) 0.80 Cr3+ (aq) + Cr²+ (aq) Fe+(aq) + 3e...
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