Question

Thermally Induced Stress- Example 11.9 A steel bolt through a 25-in.-long aluminum tube has the nut turned on until it just touches the end of the tube. No stress is introduced bolt or the tube. The temperature of the assembly is raised from 60F to 70 F. If the cross-sectional area e bolt is 0.08 in.2 and the cross-sectional area of the tube s 0.25 in., find the stress induced in the bolt and tube by the temperature change. Es 30 x 10pEA 10 x 10 psi, 6.5 x 10per F, aA as 13.0 x 10 per F

Answer 1

Given & length of Aluminium tube = 25 inch - Changin temperature (AT) = 70-60 = 10°F As = Grossectional area of boht := 0.08 in2 AA Crossectional area of tube = 0.25 in? Es = 30x100 psi Pa = 10 XLOS Psi as = 6.5x100 per of XA = 13 X 100 per of Tension in aluminium - Compression in steel ZA. AA = bs. As = 2A = 25. (As) Es EA BA=0.3265] using relation 2 + 3 = (dA-Ls) at 25 + 0.32bs = (13-6.5X10 x 10 30x106 10x106 bg = 994.89 Psi | BA= 0.32 X 994.89 12A = 318.36 Psi Stress in steel bolt is 994.89 Psi . Stress in Aluminium tube is 318.36 Psi