Question

d. 95% conlidence interval lor ces the length of colds. 200 participants are 2. A researcher believes that taking vitamin C reduces the length of cold randomly assigned so that 100 are in the experimental group take 100 are in the experimental oroun (take vitamin C) and 100 are in control group (take a placebo). Over the course of a vear the lengths of each participants are recorded, with the following results: Vitamin C - 6 days Si= 2 days Control Group X2=8 days $2= 3 days Testing at significance level a- .05, Find: a. Ho, H. b. standard error of XI - X2 c. Z value d. P value e. Conclusion

Answer 1

vite mt 100 conta Group me=100 = 8 days Se o 3 days x = 6 day Si= aday 20.06 Ho: Mi = Hz Hy i Muce cu soft tarted test) stand.oed more of 3-6, - se s t o = 0-3605 40.361) SE = = 0.3605 le t -value a atz. 6-6 = - 5.547 SE 0.361 - 5.55 r Population standard deviation P-value= P(t=-5-56) is unknow so It distribution 0.00] Lis used Prahu La=0005 df = 172 (4) Reject to conclusion. The data provide sufficient evidence at a=0008 level of significance evat hoa vitamin c reduces the hugth of cold. - de sufficient df. London $272 Ls