Question

C_3H_8 + 5O_2 rightarrow 3 CO_2 + 4 H_2O For the above reaction, 88 g of C_3H_8 is reacted with 160 g of O_2. What would be the theoretical yield of CO_2? A) 264 g B) 132 g C) 66 g D) 33 g

Answer 1

LT 2 .11 LTEM 27% 9:12 PM KB/s Done ANSWER:- option b C3H8(g) 502(g) ---> 3CO2(g) + 4H20(g) We can compute the mass of a product with each mass of reactant. The actual amount of product will be the smaller of the two, and the reactant that gives the smaller amount of product will be the limiting reactant. 88g C3H8 x (1 mol C3H8 /44.0 g C3H8) x (3 mol CO2/1 mol C3H8) x (44.0g C3H8/1 mol C3H8) 264 CO2 160g O2 x (1 mol O2/32.0 g O2) x (3 mol CO2/ 5 mol O2) x (44.0g C3H8/ 1 mol C3H8) - 132g CO2 Clearly, 132 grams is less, and so that will be the theoretical yield of this reaction answer is 132g Wrap Text Tools Keyboard