Question

El momento de inercia del área sombreada con respecto al eje x dado en cm 4 es * -6.3cm -11.3cm 10.5cm 4.5cm R1.5cm -10.5cm 6.0cm

The moment of inertia of the shaded area with respect to the x axis given in cm^4 is?

Answer 1

- S.3em de -____ 11.3 cm - HK- HK 10.6cm 6.0 cm

Moment of inertia of BD GH about a-anies is, Igoak = + ((10.6+6.0) (4.5+4.5)) (4.St4.s)? = + 4033.8 cm I ABC = + [4 (5:3)(6)] (%)? + [{ (S.3(0] (12-24) = + 1955.7 ema I LHF = +4 [3 (1.6) (4:5)] (1,5}} = + 80.49375 cm" Idek = +{ [()(45)] (4:58 + [:() (4:5)) (62–151)} = +501. 1875 cm4 I EKSF = + f[6) (.5) (453"} 1 EKGF = = + 182.25 cm 4

Is = -f(x (1.5*] (1;$3€ + [a (1.35] (4.5)4} = 147.114893 cm" 4 . a I total = Igoan + I ABC - ILHF - I dex - IEKGF -Ig = (4033.8) + (1955.1) -(80.49375) -(501.1878) ** - (182.25). -(147.114893) => I total = 5078.45386 com el This is the moment of inertia of shaded region with respect to a- anir. .