Question

This Quiz: 100 pts possible 2 of 20 (0 complete) This Question: 5 pts Question Help In a large clinical trial, 399,941 children were randomly assigned to two groups. The treatment group consisted of 199,955 children given a vaccine for a certain disease, and 33 of those children developed the disease. The other 199,986 children were given a placebo, and 125 of those children developed the disease. Consider the vaccine treatment group to be the first sample. Identify the values of n, p. q, n, P2, 92. , and q. (Type an integer or a decimal rounded to eight decimal places needed.) (Type an integer or a decimal rounded to eight decimal places needed.) (Type an integer or a decimal rounded to eight decimal places as needed.) 2= (Type an integer or a decimal rounded to eight decimal places as needed.) (Type an integer or a decimal rounded to eight decimal places as needed.) anok 1. q= (Type an integer or a decimal rounded to eight decimal places as needed.) the answer boxes. Enter your answer in each 06/13/2012 P

Answer 1

Solution

given

$\small \mathbf{n_1}$	X1	n2	X2
199955	33	86	125

n1 = 199955

$\small \mathbf{\hat p_1}=\frac{x_1}{n_1}=\frac{33}{199955}=\mathbf{{\color{Red} 0.00016504}}$

q 1-P 1-0.00016504 0.99983496

$\small \mathbf{n_2}=\mathbf{{\color{Red} 199986}}$

$\small \mathbf{\hat p_2}=\frac{x_2}{n_2}=\frac{125}{199986}=\mathbf{{\color{Red} 0.00062504}}$

a21-p2 1-0.00062504 =0.99937496

$\small \mathbf{\bar p}=\frac{x_1+x_1}{n_1+n_2}=\frac{33+125}{199955+199986}=\frac{158}{399941}=\mathbf{{\color{Red} 0.00039506}}$

$\small \mathbf{\bar q}=1-\bar p=1-0.00039506=\mathbf{{\color{Red} 0.99960494}}$

Answer 2

Solution

given

$\small \mathbf{n_1}$	X1	n2	X2
199955	33	86	125

n1 = 199955

$\small \mathbf{\hat p_1}=\frac{x_1}{n_1}=\frac{33}{199955}=\mathbf{{\color{Red} 0.00016504}}$

q 1-P 1-0.00016504 0.99983496

$\small \mathbf{n_2}=\mathbf{{\color{Red} 199986}}$

$\small \mathbf{\hat p_2}=\frac{x_2}{n_2}=\frac{125}{199986}=\mathbf{{\color{Red} 0.00062504}}$

a21-p2 1-0.00062504 =0.99937496

$\small \mathbf{\bar p}=\frac{x_1+x_1}{n_1+n_2}=\frac{33+125}{199955+199986}=\frac{158}{399941}=\mathbf{{\color{Red} 0.00039506}}$

$\small \mathbf{\bar q}=1-\bar p=1-0.00039506=\mathbf{{\color{Red} 0.99960494}}$