Question

Cobalt Synthesis Calculations:

Can someone help me find the answers to fill in the table on the left (and show your work if you can)? I am having trouble understanding what I need to do. Thanks!

Date Tablettebat Synthesh Sholehiometrie Calculations COMO HOMOLand HNOdaml 10 NM-2 (CO(NHOJINO. MAJ • 12 MOT Melar Mans of [Co(HMM.OVOh tamol) Mass er volume Males of Moles of Cabalt Mass of Cobalt Aegent of Reagent used Regent Used Complex That Can Be Carnplex that can be Farmed Formed fmol) Ca(NO. 6 HO o 012 GM NHOH 40 mt 3K HO 0.023 16 HNO. 30 ml 0.48 Limiting Reagent Theoretical Yield of Cobalt Complex (in glased on the limiting Reagent * NANO increases the concentration of NHLOH in the reaction. However, the amount is negligible and does not need to be included in your calculations. ΈATA TABL€2 ετρεχνιγ48 13.01359 mass of C.(N63), 6H,69) Theoretical Yeld of Cs Comp (in 9) Based On actual aver 04 hting Peace 2.53139 M55 NHA NOs (4) Mass of orude crystals +f. Her papest) 3.3102 O 13 ZY Mass (Tare)of filter fe per les Mess of Cructa crystais (g) 3.0981 Describe the crysals formed Saimon Colored, 7. Yield of crucle crystals (26) VULV 4M N ra UH (t tay 12, q5,2 Volume of Murted to prepare 1M NAADHI HAO (O L% 3 M N.4 to prepard voluut wakr added to bom NH4OH, 61. 3016 AM NADH Professor or TA signature JI Volume of loM ANOg reeded, Clude 25% asm EXCESS Mass of fel crystals + filter Paper (9) 2.2305 mess of (Tere) filtr reper (9) (0.23149 Mess Of Famel orystels () 1.9984 2. Yeld of Firol crystals (7%) Describe e crystals formed Newy i pastur Professor or TA Sireture

Answer 1

According to the balanced chemical equation,2 mol of complex is produced on rxn of :

1) 2 mol Co(NO3)2.6H2O

2)10 mol NH4OH

3)1 mol H2O2

4)2 mol HNO3

As Co(NO3)2.6H2O is present in the least amount among the reactants ,so it may be the limiting reactant.To verify this fact, calculate the amount of other reactants it will react.

2 mol Co(NO3)2.6H2O reacts with 1mol H2O2,so 0.012 mol Co(NO3)2.6H2O will react with 0.012/2=0.006 mol H2O2

2 mol Co(NO3)2.6H2O reacts with 10mol NH4OH,so 0.012 mol Co(NO3)2.6H2O will react with 0.012*10=0.12 mol NH4OH

2 mol Co(NO3)2.6H2O reacts with 2 mol HNO3 ,so 0.012 mol Co(NO3)2.6H2O will react with 0.012 mol HNO3

Thus,Co(NO3)2.6H2O is the limiting reactant, and rest are excess reactant.Thus ,0.012 mol of Co(NO3)2.6H2O will produce equal moles of the complex

mass of complex formed =0.012mol*molar mass of the complex=0.012 mol*(348.116 g/mol)=4.117g

Theoretical yield based on limiting reagent=4.117g

DATA TABLE 2 Expeomenta Cobalt Mass of Cobatt Moles of Comples That Can Be Complex That Can Be Mass or Volume Moles of Rergent af Reagent Used Rengent Used Pormed Formed mot of hstng peaune un act 2.53139 Mass o 162 0 012 0012 ass of oruole cryseats+iter papsi3101 M NHOH 0.012 023 Z 0.24 0.023 0.48 Mass (Tareot fiter peper 0012 4.117 3%HO, mass of Cructa crystas (3) Descrie uz crysais formed 25 ml 30 mt 0.012 Satmon cotored Co(NO3)2 .6H20 Limiting Reagent Theoretical Yield of Cobalt Complex (in g) Based on crude crystals (%) % yLe ld the Limiting Reaent Note NelINO, increases the concentration of NH.OH in the reaction However, the amount is vcurusf wakr added tobon N13 Profes sor or TA sgrotuse VOluml of loM HNOg needed,"cludess%145mL mass of mess of (ere) fiter peper (g)23 Mess Ot kinel orustels ( a yuid of final crusta is (%) Desite rhe cnstais formed negigible and does nat need to be included in your calculations 22305 0, 23149 1.44pt inel crusals+fiter apr Prokssor or TA sgreture